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By actual division, show that each of th...

By actual division, show that each of the following rational numbers is a terminating decimal. Express each in the decimal form :
(i) `(17)/(2^(2) xx 5^(3))` (ii) `(24)/(625)`

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To show that each of the following rational numbers is a terminating decimal, we will perform actual division for each case. ### (i) \( \frac{17}{2^2 \times 5^3} \) 1. **Calculate the denominator**: \[ 2^2 = 4 \quad \text{and} \quad 5^3 = 125 \] Therefore, \[ 2^2 \times 5^3 = 4 \times 125 = 500. \] Now we rewrite the fraction: \[ \frac{17}{500}. \] 2. **Perform the division**: We need to divide 17 by 500. Since 500 is greater than 17, we start by placing a decimal point: \[ 17.000 \div 500. \] - 500 goes into 1700 (after adding two zeros) three times (3 × 500 = 1500). - Subtract: \[ 1700 - 1500 = 200. \] - Bring down another zero to make it 2000. - 500 goes into 2000 four times (4 × 500 = 2000). - Subtract: \[ 2000 - 2000 = 0. \] Thus, the division is complete. 3. **Result**: The result of the division is: \[ 0.034. \] ### (ii) \( \frac{24}{625} \) 1. **Perform the division**: We need to divide 24 by 625. Since 625 is greater than 24, we place a decimal point: \[ 24.000 \div 625. \] - 625 goes into 2400 (after adding two zeros) three times (3 × 625 = 1875). - Subtract: \[ 2400 - 1875 = 525. \] - Bring down another zero to make it 5250. - 625 goes into 5250 eight times (8 × 625 = 5000). - Subtract: \[ 5250 - 5000 = 250. \] - Bring down another zero to make it 2500. - 625 goes into 2500 four times (4 × 625 = 2500). - Subtract: \[ 2500 - 2500 = 0. \] Thus, the division is complete. 2. **Result**: The result of the division is: \[ 0.0384. \] ### Final Answers: - (i) \( \frac{17}{500} = 0.034 \) - (ii) \( \frac{24}{625} = 0.0384 \)
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