Two taps running together can fill a tank in `3(1/13)` hours. If one tap takes 3 hours more than the other to fill the tank, then how much time will each tap take to fill the tank ?

Explanation

To solve the problem of how long each tap takes to fill the tank, we can follow these steps:

### Step 1: Define Variables
Let the time taken by the first tap to fill the tank be \( x \) hours. Then, the time taken by the second tap will be \( x + 3 \) hours (since it takes 3 hours more than the first tap).

### Step 2: Find the Combined Rate
When both taps are working together, they can fill the tank in \( 3 \frac{1}{13} \) hours. We convert this mixed number into an improper fraction:
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