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The quadratic equation 2x^(2)-sqrt5x+1=0...

The quadratic equation `2x^(2)-sqrt5x+1=0` has
(a) two distinct real roots (b) two equal real roots
(c) no real roots (d) more than 2 real roots

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Given equation is `2x^(2)-sqrt5x+1=0`
Here `a=2,b=sqrt5,c=1`
`because Discriminant D"=b^(2)-4ac`
`=(-sqrt5)^(2)-4(2)(1)=5-8=-3lt0` `implies` Given equation has no real root.
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