Home
Class 10
MATHS
Solve the following quations by using qa...

Solve the following quations by using qardratic formula:
`(x-2)/(x+2)+(x+2)/(x-1)=4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \(\frac{x-2}{x+2} + \frac{x+2}{x-1} = 4\) using the quadratic formula, we will follow these steps: ### Step 1: Find a common denominator The common denominator for the fractions on the left side is \((x+2)(x-1)\). Therefore, we can rewrite the equation as: \[ \frac{(x-2)(x-1) + (x+2)(x+2)}{(x+2)(x-1)} = 4 \] ### Step 2: Cross-multiply Cross-multiplying gives us: \[ (x-2)(x-1) + (x+2)(x+2) = 4(x+2)(x-1) \] ### Step 3: Expand both sides Now, we will expand both sides of the equation: Left side: \[ (x-2)(x-1) = x^2 - x - 2x + 2 = x^2 - 3x + 2 \] \[ (x+2)(x+2) = x^2 + 4x + 4 \] Combining these: \[ x^2 - 3x + 2 + x^2 + 4x + 4 = 2x^2 + x + 6 \] Right side: \[ 4(x+2)(x-1) = 4(x^2 + 2x - x - 2) = 4(x^2 + x - 2) = 4x^2 + 4x - 8 \] ### Step 4: Set the equation to zero Now we set the equation to zero by moving all terms to one side: \[ 2x^2 + x + 6 - (4x^2 + 4x - 8) = 0 \] This simplifies to: \[ 2x^2 + x + 6 - 4x^2 - 4x + 8 = 0 \] \[ -2x^2 - 3x + 14 = 0 \] Multiplying through by -1 gives: \[ 2x^2 + 3x - 14 = 0 \] ### Step 5: Identify coefficients In the quadratic equation \(ax^2 + bx + c = 0\), we have: - \(a = 2\) - \(b = 3\) - \(c = -14\) ### Step 6: Use the quadratic formula The quadratic formula is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Substituting the values of \(a\), \(b\), and \(c\): \[ x = \frac{-3 \pm \sqrt{3^2 - 4 \cdot 2 \cdot (-14)}}{2 \cdot 2} \] ### Step 7: Calculate the discriminant Calculating the discriminant: \[ b^2 - 4ac = 9 + 112 = 121 \] ### Step 8: Substitute back into the formula Now substituting back: \[ x = \frac{-3 \pm \sqrt{121}}{4} \] \[ x = \frac{-3 \pm 11}{4} \] ### Step 9: Solve for the two possible values of \(x\) Calculating the two possible values: 1. \(x = \frac{-3 + 11}{4} = \frac{8}{4} = 2\) 2. \(x = \frac{-3 - 11}{4} = \frac{-14}{4} = -\frac{7}{2}\) ### Final Answer The solutions to the equation are: \[ x = 2 \quad \text{and} \quad x = -\frac{7}{2} \] ---
Promotional Banner

Topper's Solved these Questions

  • QUADRATIC EQUATIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 4c|12 Videos
  • QUADRATIC EQUATIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 4d|55 Videos
  • QUADRATIC EQUATIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 4a|37 Videos
  • PROBABILITY

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Very Short Answer/short Answer Questions|16 Videos
  • REAL NUMBERS

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Answer Questions|5 Videos

Similar Questions

Explore conceptually related problems

Solve the following quations by using qardratic formula: 2x^(2)-9x+7=0

Solve the following quations by using qardratic formula: (1)/(x-2)+(1)/(x-3)+(1)/(x-4)=0

Solve the following quations by using qardratic formula: x^(2)-18x+77=0

Solve the following quations by using qardratic formula: 256x^(2)-32x+1=0

Solve the following quations by using qardratic formula: 5x^(2)-19x+17=0

Solve the following quations by using qardratic formula: (2)/(3)x=-(1)/(6)x^(2)-(1)/(3)

Solve the following quations by using qardratic formula: (1)/(15)x^(2)+(5)/(3)=(2)/(3)x

Solve the following quations by using qardratic formula: abx^(2)+(b^(2)-ac)x-bc=0

Solve the following quations by using qardratic formula: p^(2)x^(2)+(p^(2)-q^(2))x-q^(2)=0

Solve the following quations by using qardratic formula: sqrt6x^(2)-4x-2sqrt6=0