If the equation `(a^2+b^2)x^2-2(a c+b d)x+c^2+d^2=0` has equal roots, then
(a)`a b=c d` (b) `a d=b c` (c) `a d=sqrt(b c)` (d)`a b=sqrt(c d)`

If the roots of the equation (a^2+b^2)x^2-2(a c+b d)x+(c^2+d^2)=0 are equal, prove that a/b=c/d

Prove that the equation x^2(a^2+b^2)+2x(a c+b d)+(c^2+d^2)=0 has no real root, if a d!=bc dot

Prove that the equation x^2(a^2+b^2)+2x(a c+b d)+(c^2+d^2)=0 has no real root, if a d!=b c .

If the roots of the equation (a^2+b^2)x^2-2b(a+c)x+(b^2+c^2)=0 are equal, then (a) 2b=a+c (b) b^2=a c (c) b=(2a c)/(a+c) (d) b=a c

If a x^2+b x+c=0 has equal roots, then c= (a) b/(2a) (b) b/(2a) (c) (-b^2)/(4a) (d) (b^2)/(4a)

The value of c for which the equation a x^2+2b x+c=0 has equal roots is (a) (b^2)/a (b) (b^2)/(4a) (c) (a^2)/b (d) (a^2)/(4b)

If c!=0 and the equation p//(2x)=a//(x+c)+b//(x-c) has two equal roots, then p can be (sqrt(a)-sqrt(b))^2 b. (sqrt(a)+sqrt(b))^2 c. a+b d. a-b

If the solution set of the inequaiton (x+4)(x-1)(x-3)(x+1)<0 is x in (a , b)uu(c , d) then (a) a+b+c+d=1 (b) a+b+c+d=2 (c) a b c d=12 (d) a b+c d=7

If a ,b ,c ,d in R , then the equation (x^2+a x-3b)(x^2-c x+b)(x^2-dx+2b)=0 has a. 6 real roots b. at least 2 real roots c. 4 real roots d. none of these

Given that a x^2+b x+c=0 has no real roots and a+b+c 0 d. c=0