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The longest side of a right angled trian...

The longest side of a right angled triangle is 4cm longer than one side and 2 cm longer than the other side. Find the longest side.

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To solve the problem step-by-step, we will define the variables and use the properties of a right-angled triangle. ### Step 1: Define the Variables Let the longest side (hypotenuse) of the right-angled triangle be denoted as \( x \) cm. According to the problem: - One side (let's call it \( a \)) is \( x - 4 \) cm (4 cm shorter than the longest side). - The other side (let's call it \( b \)) is \( x - 2 \) cm (2 cm shorter than the longest side). ### Step 2: Apply the Pythagorean Theorem In a right-angled triangle, the relationship between the lengths of the sides is given by the Pythagorean theorem: \[ x^2 = a^2 + b^2 \] Substituting the expressions for \( a \) and \( b \): \[ x^2 = (x - 4)^2 + (x - 2)^2 \] ### Step 3: Expand the Squares Now, we will expand the squares on the right-hand side: \[ x^2 = (x - 4)^2 + (x - 2)^2 \] \[ = (x^2 - 8x + 16) + (x^2 - 4x + 4) \] Combining like terms: \[ x^2 = x^2 - 8x + 16 + x^2 - 4x + 4 \] \[ = 2x^2 - 12x + 20 \] ### Step 4: Rearrange the Equation Now, we will rearrange the equation to set it to zero: \[ x^2 - (2x^2 - 12x + 20) = 0 \] \[ 0 = 2x^2 - 12x + 20 - x^2 \] \[ 0 = x^2 - 12x + 20 \] ### Step 5: Factor the Quadratic Equation Next, we will factor the quadratic equation: \[ x^2 - 12x + 20 = 0 \] We need two numbers that multiply to \( 20 \) and add up to \( -12 \). These numbers are \( -10 \) and \( -2 \): \[ (x - 10)(x - 2) = 0 \] ### Step 6: Solve for \( x \) Setting each factor to zero gives us: 1. \( x - 10 = 0 \) → \( x = 10 \) 2. \( x - 2 = 0 \) → \( x = 2 \) ### Step 7: Determine the Valid Solution Since \( x \) represents the length of the longest side, we need to ensure that it is a positive value. If we substitute \( x = 2 \) back into our expressions for the sides: - \( a = 2 - 4 = -2 \) (not valid, as length cannot be negative) - \( b = 2 - 2 = 0 \) (not valid, as length cannot be zero) Thus, the only valid solution is: \[ x = 10 \text{ cm} \] ### Conclusion The longest side of the right-angled triangle is \( 10 \) cm. ---
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