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If x=1 is a root of x^(2)+kx+5=0,...

If `x=1` is a root of `x^(2)+kx+5=0`,

A

`k= 5`

B

`k=6`

C

`k= -6`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the value of \( k \) given that \( x = 1 \) is a root of the quadratic equation \( x^2 + kx + 5 = 0 \). ### Step-by-Step Solution: 1. **Substitute the root into the equation**: Since \( x = 1 \) is a root, we can substitute \( x \) with \( 1 \) in the equation: \[ 1^2 + k(1) + 5 = 0 \] 2. **Simplify the equation**: Calculate \( 1^2 \) which is \( 1 \): \[ 1 + k + 5 = 0 \] 3. **Combine like terms**: Combine the constants \( 1 \) and \( 5 \): \[ k + 6 = 0 \] 4. **Solve for \( k \)**: Isolate \( k \) by subtracting \( 6 \) from both sides: \[ k = -6 \] Thus, the value of \( k \) is \( -6 \). ### Final Answer: The value of \( k \) is \( -6 \).
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