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Solve the equation x^(2)-45x+324=0....

Solve the equation `x^(2)-45x+324=0`.

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To solve the quadratic equation \( x^2 - 45x + 324 = 0 \), we will use the method of splitting the middle term. ### Step-by-Step Solution: 1. **Identify the coefficients**: The given equation is in the standard form \( ax^2 + bx + c = 0 \), where: - \( a = 1 \) - \( b = -45 \) - \( c = 324 \) 2. **Find two numbers that multiply to \( c \) and add up to \( b \)**: We need to find two numbers that multiply to \( 324 \) (the constant term) and add up to \( -45 \) (the coefficient of \( x \)). - The factors of \( 324 \) are: \( (1, 324), (2, 162), (3, 108), (4, 81), (6, 54), (9, 36), (12, 27), (18, 18) \). 3. **Select the correct pair**: We need a pair that adds up to \( -45 \). The pair \( -9 \) and \( -36 \) works because: - \( -9 \times -36 = 324 \) - \( -9 + (-36) = -45 \) 4. **Rewrite the equation**: We can rewrite the middle term \( -45x \) using the pair found: \[ x^2 - 9x - 36x + 324 = 0 \] 5. **Factor by grouping**: Group the terms: \[ (x^2 - 9x) + (-36x + 324) = 0 \] Factor out the common terms: \[ x(x - 9) - 36(x - 9) = 0 \] 6. **Factor out the common binomial**: \[ (x - 9)(x - 36) = 0 \] 7. **Set each factor to zero**: Now we can set each factor to zero to find the values of \( x \): - \( x - 9 = 0 \) gives \( x = 9 \) - \( x - 36 = 0 \) gives \( x = 36 \) 8. **Conclusion**: The solutions to the equation \( x^2 - 45x + 324 = 0 \) are: \[ x = 9 \quad \text{and} \quad x = 36 \]
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