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In the given figure, if AB=AC, rove that...

In the given figure, if AB=AC, rove that BE=EC.

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We know that, length of tangents from an external point are equal.
`:." "AD=AF" "…(1)`
`DB=BE" "…(2)`
`EC=FC" "…(3)`
Now, it is given that
`AB=AC`
`implies" "AD+DB=AF+FC`
`implies" "cancel(AD)+DB=cancel(AD)+EC" "`[from (1)and(3)]
`implies" "DB=EC`
`:." "BE=EC" "`[from (2), DB=BE] Hence Proved.
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