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The vertices of a Delta ABC are A(4,6), ...

The vertices of a `Delta ABC` are `A(4,6)`, `B(1,5)` and `C(7,2)`. A line is drawn to intersect sides `AB` and `AC` at `D` and `E` respectively, such that `(AD)/(AB)=(AE)/(AC)=1/4`Calculate the area of the `Delta ADE` and compare it with the area of `Delta ABC`

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The correct Answer is:
`15/32` square units
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