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If the distance between the point (x,-1)...

If the distance between the point `(x,-1)` and `(-2,2)` is 5 , then find the possible values of x .

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To solve the problem, we need to find the possible values of \( x \) such that the distance between the points \( (x, -1) \) and \( (-2, 2) \) is equal to 5. ### Step-by-Step Solution: 1. **Use the Distance Formula**: The distance \( d \) between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by: \[ d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} \] Here, \( (x_1, y_1) = (x, -1) \) and \( (x_2, y_2) = (-2, 2) \). The distance is given as 5. 2. **Set Up the Equation**: Substitute the points into the distance formula: \[ 5 = \sqrt{(x - (-2))^2 + (-1 - 2)^2} \] This simplifies to: \[ 5 = \sqrt{(x + 2)^2 + (-3)^2} \] 3. **Square Both Sides**: To eliminate the square root, square both sides of the equation: \[ 25 = (x + 2)^2 + 9 \] 4. **Rearrange the Equation**: Subtract 9 from both sides: \[ 25 - 9 = (x + 2)^2 \] \[ 16 = (x + 2)^2 \] 5. **Take the Square Root**: Take the square root of both sides: \[ \sqrt{16} = x + 2 \quad \text{or} \quad \sqrt{16} = -(x + 2) \] This gives us two equations: \[ 4 = x + 2 \quad \text{and} \quad -4 = x + 2 \] 6. **Solve for \( x \)**: For the first equation: \[ x + 2 = 4 \implies x = 4 - 2 = 2 \] For the second equation: \[ x + 2 = -4 \implies x = -4 - 2 = -6 \] 7. **Final Values**: Therefore, the possible values of \( x \) are: \[ x = 2 \quad \text{and} \quad x = -6 \] ### Conclusion: The possible values of \( x \) are \( 2 \) and \( -6 \). ---
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