find the sum of `n` terms of the series `(4-1/n)+(4-2/n)+(4-3/n)+...........`

Explanation

To find the sum of the first `n` terms of the series \( (4 - \frac{1}{n}) + (4 - \frac{2}{n}) + (4 - \frac{3}{n}) + \ldots \), we can follow these steps:

### Step 1: Identify the General Term
The general term of the series can be expressed as:
\[ a_n = 4 - \frac{n}{n} = 4 - \frac{k}{n} \quad \text{for } k = 1, 2, 3, \ldots, n \]
Thus, the first term is \( 4 - \frac{1}{n} \), the second term is \( 4 - \frac{2}{n} \), and so on.
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