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Sum of the first p, q and r terms of an A.P are a, b and c, respectively.Prove that `a/p(q-r)+b/q(r-p)+c/r(p-q)=0`

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To prove that \[ \frac{a}{p(q-r)} + \frac{b}{q(r-p)} + \frac{c}{r(p-q)} = 0 \] given that the sums of the first \( p \), \( q \), and \( r \) terms of an arithmetic progression (A.P.) are \( a \), \( b \), and \( c \) respectively, we will follow these steps: ...
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