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A man standing on the deck of a ship, which is 10m above water level. He observes the angle of elevation of the top of a hill as `60^0` and the angle of depression of the base of the hill as `30^0dot` Calculate the distance of the hill from the ship and the height of the hill.

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Let the height of the hill AB = h m and let the position of man at 10 m above the sea-level is D.
Let `BC=x m rArr DE=x m `
In right `DeltaDCB`,
tan30^(@)=(DC)/(BC) rArr 1/sqrt3=10/x rArr x=10sqrt3 m …(1)`
In right 60^(@)=(AE)/(DE) rArr sqrt3=(h-10)/x`
`:. xsqrt3=h-10 rArr10sqrt3xxsqrt3=h-10" [from(1)]"`
`rArr h=30+10=40m`
Hence, the distance of the hill from the ship id x i.e., `10sqrt3 m` and height of the hill is 40 m.
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