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Two stations due south of a leaning towe...

Two stations due south of a leaning tower which leans towards the north are at distances a and b from its foot If `alpha` and `beta` are the elevations of the top of the tower from these stations then prove that its inclination `theta` to the horizontal is given by `cottheta =(bcotalpha-acotbeta)/(b-a)`

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To solve the problem, we need to prove that the inclination \(\theta\) of the leaning tower to the horizontal is given by the equation: \[ \cot \theta = \frac{b \cot \alpha - a \cot \beta}{b - a} \] where: - \(a\) and \(b\) are the distances of the two stations from the foot of the tower, ...
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