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A 7 m long flagstaff is fixed on the top...

A 7 m long flagstaff is fixed on the top of a tower on the horizontal plane. From a point on the ground, the angles of elevation of the top and bottom of the flagstaff are `45^(@)" and " 30^(@)` respectively. Find the height of the tower.

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To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the problem We have a flagstaff of height 7 m fixed on top of a tower. We need to find the height of the tower given the angles of elevation from a point on the ground to the top and bottom of the flagstaff are 45° and 30° respectively. ### Step 2: Draw a diagram Let’s label the points: - Let point A be the point on the ground from where the angles are measured. - Let point B be the bottom of the flagstaff (top of the tower). - Let point C be the top of the flagstaff. - Let point D be the point directly below C on the ground. ### Step 3: Define the heights Let the height of the tower be \( h \). Therefore, the height of the flagstaff above the tower is 7 m, making the total height from point A to point C equal to \( h + 7 \). ### Step 4: Use the tangent function for the angles of elevation 1. For angle of elevation to the top of the flagstaff (C): \[ \tan(45^\circ) = \frac{AC}{AD} \] Here, \( AC = h + 7 \) and \( AD = CD \) (the horizontal distance from point A to point D). Since \( \tan(45^\circ) = 1 \): \[ 1 = \frac{h + 7}{CD} \implies CD = h + 7 \] 2. For angle of elevation to the bottom of the flagstaff (B): \[ \tan(30^\circ) = \frac{BC}{AD} \] Here, \( BC = h \). Since \( \tan(30^\circ) = \frac{1}{\sqrt{3}} \): \[ \frac{1}{\sqrt{3}} = \frac{h}{CD} \implies CD = h \sqrt{3} \] ### Step 5: Set the two expressions for CD equal to each other From the two equations for \( CD \): \[ h + 7 = h \sqrt{3} \] ### Step 6: Rearrange the equation Rearranging gives: \[ h \sqrt{3} - h = 7 \implies h(\sqrt{3} - 1) = 7 \] ### Step 7: Solve for h \[ h = \frac{7}{\sqrt{3} - 1} \] ### Step 8: Rationalize the denominator To rationalize: \[ h = \frac{7(\sqrt{3} + 1)}{(\sqrt{3} - 1)(\sqrt{3} + 1)} = \frac{7(\sqrt{3} + 1)}{3 - 1} = \frac{7(\sqrt{3} + 1)}{2} \] ### Step 9: Calculate the numerical value Using \( \sqrt{3} \approx 1.732 \): \[ h \approx \frac{7(1.732 + 1)}{2} = \frac{7(2.732)}{2} \approx \frac{19.124}{2} \approx 9.562 \text{ meters} \] ### Final Answer The height of the tower is approximately \( 9.562 \) meters. ---
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