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The angle of elevation of the top of a v...

The angle of elevation of the top of a vertical tower, from a point in the horizontal plane passing through the foot of the tower is `theta`. On moving towards the tower 192 metres, the angle of elevation becomes `phi`. If `tan theta=5/12" and "tanphi=3/4`, then find the height of the tower.

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To solve the problem step by step, we will use the information provided about the angles of elevation and the distances involved. ### Step 1: Understand the problem setup Let the height of the tower be \( h \) meters. The point from which the angle of elevation is \( \theta \) is at a distance \( x \) meters from the base of the tower. When the observer moves 192 meters closer to the tower, the new distance from the tower becomes \( x - 192 \) meters, and the angle of elevation is \( \phi \). ### Step 2: Use the tangent function for both angles From the definitions of the tangent function, we have: - For angle \( \theta \): \[ \tan \theta = \frac{h}{x} \] Given that \( \tan \theta = \frac{5}{12} \), we can write: \[ \frac{h}{x} = \frac{5}{12} \quad \text{(1)} \] - For angle \( \phi \): \[ \tan \phi = \frac{h}{x - 192} \] Given that \( \tan \phi = \frac{3}{4} \), we can write: \[ \frac{h}{x - 192} = \frac{3}{4} \quad \text{(2)} \] ### Step 3: Express \( h \) in terms of \( x \) From equation (1): \[ h = \frac{5}{12} x \quad \text{(3)} \] ### Step 4: Express \( h \) in terms of \( x - 192 \) From equation (2): \[ h = \frac{3}{4} (x - 192) \quad \text{(4)} \] ### Step 5: Set equations (3) and (4) equal to each other Since both (3) and (4) equal \( h \), we can set them equal: \[ \frac{5}{12} x = \frac{3}{4} (x - 192) \] ### Step 6: Solve for \( x \) First, clear the fractions by multiplying through by 48 (the least common multiple of 12 and 4): \[ 48 \cdot \frac{5}{12} x = 48 \cdot \frac{3}{4} (x - 192) \] This simplifies to: \[ 20x = 36(x - 192) \] Expanding the right side: \[ 20x = 36x - 6912 \] Rearranging gives: \[ 6912 = 36x - 20x \] \[ 6912 = 16x \] \[ x = \frac{6912}{16} = 432 \text{ meters} \] ### Step 7: Substitute \( x \) back to find \( h \) Now substitute \( x = 432 \) back into equation (3) to find \( h \): \[ h = \frac{5}{12} \cdot 432 = 180 \text{ meters} \] ### Conclusion The height of the tower is \( \boxed{180} \) meters.
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