Draw the straight lines x-y+2=0 and 3x-8y=12 on the same graph pap[er
(i) Find the point where the two lines meet each other.
(ii) Find the area of traingle foprmed by these lines and x-axis.

Explanation

We have
x-y+2=0
x=y-2
When y =0 `rArr` x=-2
when y=1 `rArr` x=-1
When y =2 `rArr` x=0
when y=3 `rArr` x=1
Table for these values :

Plot the points A(-2),B(-I,1), c(0,2),D(1,3) on the graph paper and join them
3x-8y = 12
3x=8y+12
x=8y+12
3
When , y=0 `rArr` x=4
When y =-1.5 `rArr` x=0
Tables for these values

plot the points p(4,0) and Q(0,-1.5) on the graph paper and joint them.

(i) From the graph we see that the two lines intersect each other at R-(-5.6,-3.6).
(ii) Area of triangle formed by these lines and x axis is
`ar(triangle PAR) =(1)/(2)xx"base" xx "corresponding altitude"`
`=(1)/(2)APxxMR=(1)/(2)xx(a+2)xx3.6 sq` units
=10.8 sq units.