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Factorise a(x-y)-b(x-y)....

Factorise a(x-y)-b(x-y).

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Given expression : a(x-y)-b(x-y)
Now, (x-y) is common in both terms.
`therefore` First factor is (x-y).
`therefore a(x-y)-b(x-y)=(x-y)(a-b)`
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