Home
Class 9
MATHS
Factorise ax+ay+az+bx+by+bz....

Factorise `ax+ay+az+bx+by+bz`.

Text Solution

AI Generated Solution

To factorize the expression \( ax + ay + az + bx + by + bz \), we can follow these steps: ### Step 1: Group the terms We can group the terms in pairs to identify common factors: \[ (ax + ay + az) + (bx + by + bz) \] ...
Promotional Banner

Topper's Solved these Questions

  • POLYNOMIALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Problems From NCERT/exemplar|18 Videos
  • POLYNOMIALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 2a|8 Videos
  • NUMBER SYSTEM

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (short Answer Questions)|10 Videos
  • PROBABILITY

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (very Short Answer /short Answer Questions)|10 Videos

Similar Questions

Explore conceptually related problems

Factorise: ax - bx+ ay- by

Factorise : xy - ay - ax + a^2 + bx - ab

Factorise : a^2 + ax + ab + bx

Factorise : 2a - 4b - xa - 2bx

Factorise : ab + bc + ax + cx

Factorise : (v) (ax + by )^(2) + (bx - ay)^(2)

Factorise : ax + 2bx + 3cx - 3a - 6b - 9c

Factorise : (ii) 3a^(2) x - bx + 3a^(2) - b

Factorise : 8a^(3) - b^(3) - 4ax + 2bx

If the system of equations x + ay + az = 0 bx + y + bz = 0 cx + cy + z = 0 where a, b and c are non-zero non-unity, has a non-trivial solution, then value of (a)/(1 -a) + (b)/(1- b) + (c)/(1 -c) is