Home
Class 9
MATHS
Evaluate without calculating 52^(2)....

Evaluate without calculating `52^(2)`.

Text Solution

Verified by Experts

The correct Answer is:
2704
Promotional Banner

Topper's Solved these Questions

  • POLYNOMIALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (short Answer Questions)|16 Videos
  • POLYNOMIALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 2 E|22 Videos
  • NUMBER SYSTEM

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (short Answer Questions)|10 Videos
  • PROBABILITY

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (very Short Answer /short Answer Questions)|10 Videos

Similar Questions

Explore conceptually related problems

Evaluate the following: \ ^(52)C_(52)

Evaluate without using triignometric tables,** "sin"^(2)28^(@)+"sin"^(2)62^(@)+"tan"^(2)38^(@)-"cot"^(2)52^(@)+1/(4)"sec"^(2)30^(@)

Ravi calculated 29xx51 and wrote the answer as 1079. Without calculating. Can you find if the answer is correct or not?

Without using trigonometric tables, evaluate each of the following: (sec^2 54^0-cot^2 36^0)/(cos e c^2 57^0-tan^2 33^0)+2sin^2 38^0sec^2 52^0-sin^2 45^0

without actually calculating , the cubes , find the valuse of (i) ((1)/(2))^(3)+((1)/(3))^(3)-((5)/(6))^(3) (ii) (0.2)^(3)-(0.3)^(3)+(0.1)^(3)

Without using trigonometric tables, evaluate each of the following: (sec39)/(cosec 51)+2/(sqrt(3))tan17tan38tan60tan52tan73-3(sin^2 31+sin^2 59)

Without actually calculating the cube: (-12)^3+7^3+5^3

Solve using brackets to simplify the calculations: 9xx52

Without using trigonometric tables, evaluate the following:- 2(cos58^@/sin32^@)-sqrt3((cos38^@cosec52^@)/(tan15^@tan60^@tan75^@))

Without using trigonometric table, evaluate the following: (cosec^2(90-theta)-tan^2theta)/(4(cos^2 48^@+cos^2 42^@))-(2tan^2 30^@ sec^2 52^@ sin^2 38^@)/(cosec^2 70^@-tan^2 20^@