Home
Class 9
MATHS
D is a point on the circumcircle of Delt...

D is a point on the circumcircle of `Delta ABC` in which `AB=AC` such that `B` and `D` are on opposite sides of line AC. If CD is proudced to a point E such that `CE=BD`, prove that `AD=AE`.

Text Solution

AI Generated Solution

To prove that \( AD = AE \), we will use the properties of congruent triangles. Here’s the step-by-step solution: ### Step 1: Identify the Given Information We are given: - \( AB = AC \) (since triangle \( ABC \) is isosceles) - \( CD \) is extended to point \( E \) such that \( CE = BD \) - \( B \) and \( D \) are on opposite sides of line \( AC \) ...
Promotional Banner

Topper's Solved these Questions

  • CIRCLE

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 10a|22 Videos
  • CIRCLE

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 10b|19 Videos
  • AREA OF PARALLELOGRAMS AND TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (long Answer Question)|5 Videos
  • CO-ORDINATE GEOMETRY

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise|8 Videos

Similar Questions

Explore conceptually related problems

D is a point on the circumcircle of A B C in which A B=A C such that B\ a n d\ D are on the opposite side of line A C . If C D is produced to a point E such that C E=B D , prove that A D=A E .

D is any point on side AC of a Delta ABC with AB = AC .Show that CD lt BD .

In a triangle ABC,D is the mid - point of BC, AD is produced upto E so that DE = AD. Prove that : AB=EC

In a Delta ABC , BD is the median to the side AC, BD is produced to E such that BD = DE. Prove that : AE is parallel to BC.

D is a point in side BC of triangle ABC. If AD gt AC , show that AB gt AC .

Any point D is taken on the side BC of a Delta ABC and AD is produced to E such that AD = DE , prove that area of Delta BCE = area of Delta ABC ,

ABC is a triangle in which AB = AC and D is a point on AC such that BC^2 = AC xx CD .Prove that BD = BC .

D and E are points on sides AB and AC respectively of Delta A B C such that a r\ (D B C)\ =\ a r\ (E B C) . Prove that D E||B C .

In DeltaABC, AB = AC and D is a point in BC so that BD=CD . Prove that AD bisects angleBAC .

If D id the mid-point of the side BC of a triangle ABC and AD is perpendicular to AC , then