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ABCD is a parallelogram . The circle pas...

ABCD is a parallelogram . The circle passing through the vertices. A, B and C intersects CD (or CD produced) at E. Prove that `AE=AD`.

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To prove that \( AE = AD \) in the given parallelogram \( ABCD \) with a circle passing through vertices \( A, B, \) and \( C \) intersecting line \( CD \) (or its extension) at point \( E \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the properties of the parallelogram**: In parallelogram \( ABCD \), opposite angles are equal. Therefore, we have: \[ \angle A = \angle C \quad \text{and} \quad \angle B = \angle D ...
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