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A hemispherical bowl is made of steel 0.25cm thick. The inside radius of the bowl is 5cm. Find the volume of steel used in making the bowl.

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Outer radius of the bowl = Inner radius + Thickness
`= (5+0.25) cm`
`= 5.25 cm`
Outer curved surface area of the bowl `= 2pi r^(2)`
`= 2xx(22)/(7)xx5.25xx5.25 cm^(2)`
`= 173.25 cm^(2)`
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