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The circumference of the base of a cone ...

The circumference of the base of a cone is `24 pi cm` and its vertical height is 5 cm. Find its slant height.

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To find the slant height of the cone, we will follow these steps: ### Step 1: Identify the given values - Circumference of the base of the cone = \( 24\pi \) cm - Vertical height of the cone (h) = 5 cm ### Step 2: Use the formula for the circumference of a circle The formula for the circumference \( C \) of a circle is given by: \[ C = 2\pi r \] Where \( r \) is the radius of the base of the cone. ### Step 3: Set up the equation From the problem, we have: \[ 2\pi r = 24\pi \] ### Step 4: Simplify the equation to find the radius We can divide both sides by \( 2\pi \): \[ r = \frac{24\pi}{2\pi} = 12 \text{ cm} \] So, the radius \( r \) of the cone is 12 cm. ### Step 5: Use the Pythagorean theorem to find the slant height In a right triangle formed by the radius, height, and slant height of the cone, we can apply the Pythagorean theorem: \[ L^2 = r^2 + h^2 \] Where: - \( L \) is the slant height - \( r \) is the radius (12 cm) - \( h \) is the height (5 cm) ### Step 6: Substitute the known values into the equation Substituting the values we have: \[ L^2 = 12^2 + 5^2 \] \[ L^2 = 144 + 25 \] \[ L^2 = 169 \] ### Step 7: Solve for the slant height To find \( L \), take the square root of both sides: \[ L = \sqrt{169} = 13 \text{ cm} \] ### Conclusion The slant height of the cone is \( 13 \) cm. ---
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NAGEEN PRAKASHAN ENGLISH-SURFACE AREA AND VOLUME-Exercise 13c
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