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Find the total surface area of a right circular cone whose slant height is 25 cm and area of base is `154 cm^(2)`.

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To find the total surface area of a right circular cone, we will follow these steps: ### Step 1: Understand the formula for total surface area of a cone The total surface area (TSA) of a right circular cone is given by the formula: \[ \text{TSA} = \pi r^2 + \pi r l \] where: - \( r \) is the radius of the base of the cone, - \( l \) is the slant height of the cone. ### Step 2: Identify the given values From the problem, we know: - Slant height \( l = 25 \, \text{cm} \) - Area of the base \( = 154 \, \text{cm}^2 \) ### Step 3: Relate the area of the base to the radius The area of the base of the cone is given by: \[ \text{Area of base} = \pi r^2 \] Since the area of the base is given as \( 154 \, \text{cm}^2 \), we can set up the equation: \[ \pi r^2 = 154 \] Using \( \pi \approx \frac{22}{7} \), we can write: \[ \frac{22}{7} r^2 = 154 \] ### Step 4: Solve for \( r^2 \) To find \( r^2 \), we multiply both sides by \( \frac{7}{22} \): \[ r^2 = 154 \times \frac{7}{22} \] Calculating this gives: \[ r^2 = 154 \times \frac{7}{22} = 49 \] ### Step 5: Calculate \( r \) Now, take the square root of \( r^2 \) to find \( r \): \[ r = \sqrt{49} = 7 \, \text{cm} \] ### Step 6: Substitute \( r \) and \( l \) into the TSA formula Now that we have \( r \) and \( l \), we can substitute these values into the TSA formula: \[ \text{TSA} = \pi r^2 + \pi r l \] Substituting the values: \[ \text{TSA} = \frac{22}{7} \times 7^2 + \frac{22}{7} \times 7 \times 25 \] ### Step 7: Calculate each term Calculating the first term: \[ \frac{22}{7} \times 7^2 = \frac{22}{7} \times 49 = 154 \] Calculating the second term: \[ \frac{22}{7} \times 7 \times 25 = \frac{22 \times 25}{1} = 550 \] ### Step 8: Add both terms to find TSA Now, add both terms together: \[ \text{TSA} = 154 + 550 = 704 \, \text{cm}^2 \] ### Final Answer The total surface area of the right circular cone is: \[ \text{TSA} = 704 \, \text{cm}^2 \] ---
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NAGEEN PRAKASHAN ENGLISH-SURFACE AREA AND VOLUME-Exercise 13c
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