Find the area of four walls of a room whose length is 6 m, breadth is 5 m and heigth is 4 m.

Answer

To find the area of the four walls of a room with given dimensions, we can follow these steps:

### Step 1: Understand the Shape
The room is in the shape of a cuboid. The four walls consist of two pairs of opposite walls.

### Step 2: Identify the Dimensions
The dimensions provided are:
- Length (l) = 6 m
- Breadth (b) = 5 m
- Height (h) = 4 m

### Step 3: Use the Formula for Curved Surface Area
The formula for the curved surface area (CSA) of a cuboid (which represents the area of the four walls) is given by:
\[ \text{CSA} = 2h(l + b) \]

### Step 4: Substitute the Values into the Formula
Now, substitute the values of height, length, and breadth into the formula:
- Height (h) = 4 m
- Length (l) = 6 m
- Breadth (b) = 5 m

So,
\[ \text{CSA} = 2 \times 4 \times (6 + 5) \]

### Step 5: Calculate the Sum of Length and Breadth
Calculate \( l + b \):
\[ l + b = 6 + 5 = 11 \]

### Step 6: Calculate the Curved Surface Area
Now substitute back into the formula:
\[ \text{CSA} = 2 \times 4 \times 11 \]
\[ \text{CSA} = 8 \times 11 \]
\[ \text{CSA} = 88 \, \text{m}^2 \]

### Step 7: State the Final Answer
The area of the four walls of the room is:
\[ \text{Area} = 88 \, \text{m}^2 \]

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