A school auditorium is 40 m long, 30 m broad and 12 m high. If each student requires `1.2 m^(2)` of the floor area, find the maximum number of students who can be accommodated in this auditorium.

Answer

To find the maximum number of students that can be accommodated in the auditorium, we will follow these steps:

### Step 1: Calculate the Floor Area of the Auditorium
The floor area of the auditorium can be calculated using the formula:
\[ \text{Floor Area} = \text{Length} \times \text{Breadth} \]
Given:
- Length = 40 m
- Breadth = 30 m

Substituting the values:
\[ \text{Floor Area} = 40 \, \text{m} \times 30 \, \text{m} = 1200 \, \text{m}^2 \]

### Step 2: Determine the Area Required per Student
Each student requires a floor area of:
\[ 1.2 \, \text{m}^2 \]

### Step 3: Calculate the Maximum Number of Students
To find the maximum number of students that can be accommodated, we divide the total floor area by the area required per student:
\[ \text{Maximum Number of Students} = \frac{\text{Floor Area}}{\text{Area per Student}} = \frac{1200 \, \text{m}^2}{1.2 \, \text{m}^2} \]

Calculating this gives:
\[ \text{Maximum Number of Students} = 1000 \]

### Final Answer
The maximum number of students that can be accommodated in the auditorium is:
\[ \boxed{1000} \]