Find the centre and radius of the circle `3x^(2) +3y^(2) - 6x +9y - 8 =0`.

Explanation

To solve the problem of finding the center and radius of the circle given by the equation \(3x^2 + 3y^2 - 6x + 9y - 8 = 0\), we can follow these steps:

### Step 1: Simplify the Equation
First, we will divide the entire equation by 3 to simplify it:

\[ \frac{3x^2}{3} + \frac{3y^2}{3} - \frac{6x}{3} + \frac{9y}{3} - \frac{8}{3} = 0 \]
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