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Find the equation of a circle which pass...

Find the equation of a circle which passes through the point (3, 2) and concentric with the circle `x^(2)+y^(2)-4x +2y - 1=0`.

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To find the equation of the circle that passes through the point (3, 2) and is concentric with the circle given by the equation \(x^2 + y^2 - 4x + 2y - 1 = 0\), we can follow these steps: ### Step 1: Identify the center of the given circle The general form of the equation of a circle is: \[ x^2 + y^2 + 2gx + 2fy + c = 0 \] From the given equation \(x^2 + y^2 - 4x + 2y - 1 = 0\), we can identify: ...
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