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Find the equation of a circle which pass...

Find the equation of a circle which passes the centre of the circle `x^(2)+y^(2)-6x =1` and concentric with the circle `2x^(2)+2y^(2)-8x +12y -1=0`.

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To find the equation of the circle that passes through the center of the first circle and is concentric with the second circle, we will follow these steps: ### Step 1: Find the center of the first circle The equation of the first circle is given as: \[ x^2 + y^2 - 6x = 1 \] ...
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