Home
Class 11
MATHS
If e(1)ande(2) be the eccentricities of ...

If `e_(1)ande_(2)` be the eccentricities of the ellipses `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1and(x^(2))/(a^(2))+(4y^(2))/(b^(2))=1` respectively then prove that `3=4e_(2)^(2)-e_(1)^(2)`.

Text Solution

AI Generated Solution

To solve the problem, we need to find the eccentricities \( e_1 \) and \( e_2 \) of the given ellipses and then prove that \( 3 = 4e_2^2 - e_1^2 \). ### Step 1: Identify the equations of the ellipses The equations of the ellipses given are: 1. \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) (Ellipse 1) 2. \( \frac{x^2}{a^2} + \frac{4y^2}{b^2} = 1 \) (Ellipse 2) ...
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTION

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Example|3 Videos
  • CONIC SECTION

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 11A|37 Videos
  • COMPLEX NUMBERS AND QUADRATIC EQUATION

    NAGEEN PRAKASHAN ENGLISH|Exercise MISCELLANEOUS EXERCISE|20 Videos
  • INTRODUCTION OF THREE DIMENSIONAL GEOMETRY

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|6 Videos

Similar Questions

Explore conceptually related problems

If e' is the eccentricity of the ellipse (x^(2))/(a^(2)) + (y^(2))/(b^(2)) =1 (a gt b) , then

Statement- 1 : If 5//3 is the eccentricity of a hyperbola, then the eccentricity of its conjugate hyperbola is 5//4 . Statement- 2 : If e and e' are the eccentricities of hyperbolas (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 and (x^(2))/(a^(2))-(y^(2))/(b^(2))=-1 respectively, then (1)/(e^(2))+(1)/(e'^(2))=1 .

If the eccentricity of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1and(y^(2))/(b^(2))-(x^(2))/(a^(2))=1" are "e_(1)ande_(2) respectively then prove that : (1)/(e_(1)^(2))+(1)/(e_(2)^(2))=1

If e is eccentricity of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 (where,a lt b), then

The eccentricity of te ellipse (x^(2))/(16) + (y^(2))/(4) = 1 is _______

If radii of director circle of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 are in the ratio 1:3 and 4e_(1)^(2)-e_(2)^(2)=lambda , where e_1 and e_2 are the eccetricities of ellipse and hyperbola respectively, then the value of lambda is

The eccentricity of the ellipse x^(2)+4y^(2)+8y-2x+1=0 , is

If e_(1) and e_(2) are the eccentricities of the ellipse (x^(2))/(18)+(y^(2))/(4)=1 and the hyperbola (x^(2))/(9)-(y^(2))/(4)=1 respectively and (e_(1), e_(2)) is a point on the ellipse 15x^(2)+3y^(2)=k , then the value of k is equal to

If e_(1) and e_(2) are eccentricities of the hyperbolas xy=c^(2) and x^2-y^(2)=a^(2) then e_(1)^(2)+e_(2)^(2)=

Eccentricity of the ellipse 4x^2+y^2-8x+2y+1=0 is