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x^(2)=6y. Find latus rectum and axis of ...

`x^(2)=6y`. Find latus rectum and axis of parabola

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Given equation : `x^(2)=6y`
Comparing with `x^(2)=4ay`
`4a=6rArra=(3)/(2)`
`:. "Coordinates of focus" -=(0,a)-=(0,(3)/(2))`
Axis of parabola : : x=0
Equation of directrix :y+a=0
`rArry+(3)/(2)=0" "rArr" "2y+3=0`
Length of latus rectum, 4a
`=4xx(3)/(2)=6`
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