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(lim)(z->1)(z^(1/3)-1)/(z^(1/6)-1)...

`(lim)_(z->1)(z^(1/3)-1)/(z^(1/6)-1)`

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`underset(zrarr1)"lim"(z^(1//3)-1)/(z^(1//6)-1) ((0)/(0))`
`=underset(Zrarr1)"lim"((z^(1//6)^(2)-(1)^(2)))/(z^(1//6)-1)`
`=underset(zrarr1)"lim"((z^(1//6)-1)(z^(1//6)+1))/(z^(1//6)-1)`
`=underset(xrarr1)"lim"(z^(1//6)+1)=1+1= 2`.
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