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lim(xrarrpi) (sin(pi-x))/(pi(pi-x))...

`lim_(xrarrpi) (sin(pi-x))/(pi(pi-x))`

Text Solution

Verified by Experts

`underset(xrarrpi)"lim"(sin(pi-x))/(pi(pi-x))`
`=underset(yrarr0)"lim"(siny)/(pi.y)`
`=(1)/(pi)xx1`
`=(1)/(pi)`
Let `pi-x=y`
`therefore xrarrpi`
`rArr yrarrpi-pi`
`rArr yrarr0`
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