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A rectangular paper of 22 cm xx 12 cm i...

A rectangular paper of 22 cm `xx` 12 cm is folded in two different ways and formed two cylinders .
(i) Find the ratio of the volumes of two cylinders
(ii) Find the difference of the volumes of two cylinders.

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To solve the problem, we will follow these steps: ### Step 1: Determine the dimensions of the two cylinders formed by folding the rectangular paper. 1. **Folding along the breadth (12 cm)** - Height (h1) = 22 cm - Circumference = 12 cm - Using the formula for circumference: \( C = 2\pi r \) - Therefore, \( 2\pi r = 12 \) - Solving for radius (r1): \[ r_1 = \frac{12}{2\pi} = \frac{6}{\pi} \] 2. **Folding along the length (22 cm)** - Height (h2) = 12 cm - Circumference = 22 cm - Using the formula for circumference: \( C = 2\pi r \) - Therefore, \( 2\pi r = 22 \) - Solving for radius (r2): \[ r_2 = \frac{22}{2\pi} = \frac{11}{\pi} \] ### Step 2: Calculate the volumes of both cylinders. 1. **Volume of the first cylinder (V1)** - Using the formula for the volume of a cylinder: \( V = \pi r^2 h \) - Substituting the values for the first cylinder: \[ V_1 = \pi \left(\frac{6}{\pi}\right)^2 \cdot 22 \] - Simplifying: \[ V_1 = \pi \cdot \frac{36}{\pi^2} \cdot 22 = \frac{792}{\pi} \] 2. **Volume of the second cylinder (V2)** - Substituting the values for the second cylinder: \[ V_2 = \pi \left(\frac{11}{\pi}\right)^2 \cdot 12 \] - Simplifying: \[ V_2 = \pi \cdot \frac{121}{\pi^2} \cdot 12 = \frac{1452}{\pi} \] ### Step 3: Find the ratio of the volumes of the two cylinders. - The ratio \( \frac{V_1}{V_2} \): \[ \frac{V_1}{V_2} = \frac{\frac{792}{\pi}}{\frac{1452}{\pi}} = \frac{792}{1452} \] - Simplifying the ratio: \[ \frac{792 \div 36}{1452 \div 36} = \frac{22}{40.5} = \frac{11}{20.25} \approx \frac{11}{20} \] ### Step 4: Find the difference of the volumes of the two cylinders. - The difference \( V_1 - V_2 \): \[ V_1 - V_2 = \frac{792}{\pi} - \frac{1452}{\pi} = \frac{792 - 1452}{\pi} = \frac{-660}{\pi} \] - Converting to a numerical value (using \( \pi \approx 3.14 \)): \[ \frac{-660}{3.14} \approx -210.38 \text{ cm}^3 \] ### Final Answers: 1. **Ratio of the volumes**: \( \frac{11}{20} \) 2. **Difference of the volumes**: \( 210 \text{ cm}^3 \)

To solve the problem, we will follow these steps: ### Step 1: Determine the dimensions of the two cylinders formed by folding the rectangular paper. 1. **Folding along the breadth (12 cm)** - Height (h1) = 22 cm - Circumference = 12 cm - Using the formula for circumference: \( C = 2\pi r \) ...
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