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(a) How many balls of radius 1 cm can be...

(a) How many balls of radius 1 cm can be drawn by melting metallic sphere of radius 3 cm?
(b) The small spherical balls of diameter 0.6 cm are drawn by melting solid metallic sphere of 3cm radius .Find the number of small balls constructed.

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To solve the problem step by step, we will break it down into two parts as given in the question. ### Part (a): Finding the number of balls of radius 1 cm from a metallic sphere of radius 3 cm 1. **Calculate the volume of the metallic sphere.** - The formula for the volume \( V \) of a sphere is: \[ V = \frac{4}{3} \pi r^3 \] - Here, the radius \( r \) of the metallic sphere is 3 cm. - Substituting the value into the formula: \[ V_{\text{sphere}} = \frac{4}{3} \pi (3)^3 = \frac{4}{3} \pi (27) = 36\pi \text{ cm}^3 \] 2. **Calculate the volume of one small ball of radius 1 cm.** - Using the same volume formula for a sphere: \[ V_{\text{ball}} = \frac{4}{3} \pi (1)^3 = \frac{4}{3} \pi (1) = \frac{4}{3} \pi \text{ cm}^3 \] 3. **Determine the number of small balls that can be made.** - The number of balls is given by the ratio of the volume of the metallic sphere to the volume of one small ball: \[ \text{Number of balls} = \frac{V_{\text{sphere}}}{V_{\text{ball}}} = \frac{36\pi}{\frac{4}{3}\pi} \] - Simplifying this: \[ = \frac{36}{\frac{4}{3}} = 36 \times \frac{3}{4} = 27 \] ### Part (b): Finding the number of balls of diameter 0.6 cm from a metallic sphere of radius 3 cm 1. **Calculate the radius of the small ball.** - The diameter of the small ball is 0.6 cm, so the radius \( r \) is: \[ r = \frac{0.6}{2} = 0.3 \text{ cm} \] 2. **Calculate the volume of one small ball of radius 0.3 cm.** - Using the volume formula: \[ V_{\text{small ball}} = \frac{4}{3} \pi (0.3)^3 = \frac{4}{3} \pi (0.027) = \frac{0.108}{3} \pi = 0.036 \pi \text{ cm}^3 \] 3. **Determine the number of small balls that can be made.** - Using the volume of the metallic sphere calculated earlier: \[ \text{Number of small balls} = \frac{V_{\text{sphere}}}{V_{\text{small ball}}} = \frac{36\pi}{0.036\pi} \] - Simplifying this: \[ = \frac{36}{0.036} = 1000 \] ### Final Answers: - (a) The number of balls of radius 1 cm is **27**. - (b) The number of balls of diameter 0.6 cm is **1000**.
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NAGEEN PRAKASHAN ENGLISH-VOLUME AND SURFACE AREA OF SOLIDS-Exercise
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  5. A metallic sphere of radus 4 cm and a metallic cone of base readius 3 ...

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  6. How many solid speherical balls of radus 3.5 cm can be recast by melt...

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  10. How many metallic cones of radius 3 cm and height 13.5 cm are required...

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  11. The inner radius of a hemispherical cup is 9 cm and it is completely ...

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  12. Two metallic cones of equal radii 2.1 cm and heights 4.1 cm and 4.3 cm...

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  13. Threee metallic cones of radius 2cm and height 9cm are melted and reca...

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  14. Threee metallic cones of radius 2cm and height 9 cm are melted and rec...

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  15. A metallic cone is melted and recast in to a cylinder of same radius a...

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  16. A cone of height 15 cm is melted and reacast in to cylinder of same ba...

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  17. A cone of same height and same base radius is cut from a cylinder of h...

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  18. The heights of two cones are same and equal to 6cm .Their radii are 4c...

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  19. Find the volume of a cube whose diagonal is 17.32 metre.

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  20. The radius of a spherical ball of iron is 1.5 cm. It is melted and rec...

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