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Find the values of the following : i) ...

Find the values of the following :
i) `tan (19pi)/3 `
ii) `sec(-22pi)/3`

Text Solution

Verified by Experts

i) `tan(19pi)/3= tan(19 xx 180^(@))/(3)`
`=tan(1140^(@))`
`=tan(3 xx 360^(@) +60^(@))`
`=tan60^(@)=sqrt(3)`
ii) `sec(-22pi)/(3)=sec(22pi)/(3)=sec(22 xx 180^(@))/(3)`
`=sec1320^(@)`
`=sec(3 xx 360^(@) + 240^(@))`
`=sec240^(@)=sec(180^(@)+60^(@))`
`=-sec60^(@)=-2` Ans.
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