If `sinA=3/5, cosB=-12/13`, where `A in (0,pi/2) B in (pi,(3pi)/2)` ,then evaluate the following:
`i) sin(A-B)`
`ii) cos(A-B)`
`iii) tan(A+B)`

Explanation

To solve the problem, we will evaluate the following expressions given `sinA = 3/5` and `cosB = -12/13`, where `A` is in the first quadrant and `B` is in the third quadrant.

### Step 1: Find `cosA`
We know that:
\[ \sin^2 A + \cos^2 A = 1 \]
Given `sinA = 3/5`, we can substitute this value:
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