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0 < A ,B < pi/4 ,cos (A+B) =4/5, sin (A-...

`0 < A ,B < pi/4 ,cos (A+B) =4/5, sin (A-B) =5/13 => tan 2A=`

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To solve the problem step by step, we need to find the value of \( \tan 2A \) given that \( \cos(A + B) = \frac{4}{5} \) and \( \sin(A - B) = \frac{5}{13} \). ### Step 1: Find \( \tan(A + B) \) We know that: \[ \tan(A + B) = \frac{\sin(A + B)}{\cos(A + B)} \] ...
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