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If n. sin(A+2B)=sinA, then prove that: t...

If n. `sin(A+2B)=sinA`, then prove that: `tan(A+B)=(1+n)/(1-n).tanB`

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To prove that if \( n \sin(A + 2B) = \sin A \), then \( \tan(A + B) = \frac{1 + n}{1 - n} \tan B \), we can follow these steps: ### Step 1: Start with the given equation We have the equation: \[ n \sin(A + 2B) = \sin A \] ...
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