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Prove that: (sec4A-1)/(sec8A-1)=tan2A....

Prove that:
`(sec4A-1)/(sec8A-1)=tan2A. cot8A`

Text Solution

AI Generated Solution

To prove that \(\frac{\sec 4A - 1}{\sec 8A - 1} = \tan 2A \cdot \cot 8A\), we will start with the left-hand side (LHS) and manipulate it to reach the right-hand side (RHS). ### Step-by-Step Solution: 1. **Start with LHS:** \[ \text{LHS} = \frac{\sec 4A - 1}{\sec 8A - 1} \] ...
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