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In DeltaABC, tanA+tanB+tanC=tanAtanBta...

In `DeltaABC`,
`tanA+tanB+tanC=tanAtanBtanC`

Text Solution

Verified by Experts

In `DeltaABC`,
`A+B+C=180^(@)`
`rArr A+B=180^(@)-C)`
`rArr tan(A+B)=tan(180^(@)-C)`
`rArr (tanA+tanB)/(1-tanAtanB)=-tanC`
`rArr tanA+tanB=-tanC+tanBtanC`
`rArr tanA+tanB+tanC=tanAtanBtanC` Hence proved.
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