Solve: `sin3theta=sin2theta`

Explanation

To solve the equation \( \sin(3\theta) = \sin(2\theta) \), we can use the property that if \( \sin A = \sin B \), then:

\[ A = B + 2n\pi \quad \text{or} \quad A = \pi - B + 2n\pi \]

for any integer \( n \).

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