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In DeltaABC, prove that: bsinB-c sinC=as...

In `DeltaABC`, prove that: `bsinB-c sinC=asin(B-C)`

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To prove that in triangle \( \Delta ABC \), \( b \sin B - c \sin C = a \sin(B - C) \), we will follow these steps: ### Step 1: Write down the LHS We start with the left-hand side (LHS) of the equation: \[ LHS = b \sin B - c \sin C \] ...
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