In `DeltaABC, a=2, b=sqrt(6)` and `c=sqrt(3)+1`, find `angleA`.

Explanation

To find angle A in triangle ABC where \( a = 2 \), \( b = \sqrt{6} \), and \( c = \sqrt{3} + 1 \), we will use the cosine rule. The cosine rule states:

\[ \cos A = \frac{b^2 + c^2 - a^2}{2bc} \]

### Step 1: Calculate \( b^2 \), \( c^2 \), and \( a^2 \)

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