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In DeltaABC, prove that: cot\ A/2+cot\ ...

In `DeltaABC`, prove that: `cot\ A/2+cot\ B/2+cot\ C/2=((a+b+c)^(2))/(4Delta)`

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To prove that in triangle \( \Delta ABC \): \[ \cot \frac{A}{2} + \cot \frac{B}{2} + \cot \frac{C}{2} = \frac{(a+b+c)^2}{4\Delta} \] where \( \Delta \) is the area of the triangle, we will follow these steps: ...
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