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Solve: sin2theta=sin((2pi)/(3)-theta)...

Solve: `sin2theta=sin((2pi)/(3)-theta)`

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To solve the equation \( \sin 2\theta = \sin\left(\frac{2\pi}{3} - \theta\right) \), we can use the property of sine functions. The general solution for \( \sin A = \sin B \) is given by: \[ A = n\pi + (-1)^n B \] where \( n \) is any integer. ...
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