Solve it
`sin((k+1)/2)theta-sin((k-1)/2)theta=sintheta`

Explanation

To solve the equation \( \sin\left(\frac{(k+1)}{2}\theta\right) - \sin\left(\frac{(k-1)}{2}\theta\right) = \sin\theta \), we can follow these steps:

### Step 1: Apply the sine subtraction formula
We can use the sine subtraction formula, which states that:
\[ \sin A - \sin B = 2 \cos\left(\frac{A + B}{2}\right) \sin\left(\frac{A - B}{2}\right) \]
Let \( A = \frac{(k+1)}{2}\theta \) and \( B = \frac{(k-1)}{2}\theta \).
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