find the general values of '`theta`' from the following equations`sqrt(3)tan2theta+sqrt(3)tan3theta+tan2thetatan3theta=1`

Explanation

To solve the equation \( \sqrt{3} \tan 2\theta + \sqrt{3} \tan 3\theta + \tan 2\theta \tan 3\theta = 1 \), we will follow these steps:

### Step 1: Rearrange the Equation
We start with the given equation:
\[ \sqrt{3} \tan 2\theta + \sqrt{3} \tan 3\theta + \tan 2\theta \tan 3\theta = 1 \]
We can rearrange it to isolate the terms involving \( \tan 2\theta \) and \( \tan 3\theta \):
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